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CS15-213labs-bomb-lab

关于课程

这门课程围绕 CSAPP 展开。

书本相关的所有信息,你可以在 这里 找到。

你可以在 Bilibili 或者 YouTube 查看所有的课程视频,Bilibili附带中文字幕。

建议看完相应的章节然后去做相应的实验。大名鼎鼎的 CSAPP 的作者即是这门课程的讲师。你可以在 这里 找到实验相关的所有内容。

这门课程的实验代码可以在我的 Github 找到我的所有解答及相关资料。本次实验相关代码在 ./bomb 文件夹下。

bomb lab

文档

点击 这里, 然后点击标红处 Self-Study Handout 即可下载此次实验对应的文档。

解压之后文件夹对应目录:

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➜  下载 tree bomb       
bomb
├── bomb
├── bomb.c
└── README

0 directories, 3 files
  • bomb: 可执行文件
  • bomb.c: 对应的部分 C 代码
  • README: 本次实验的简单说明

内容

bomb目标代码文件运行时提示用户输入6个不同字符串,其中任意一个不正确炸弹会爆炸,也就意味着实验的失败。我们需要通过逆向工程来拆除炸弹,需要使用 gdb 和 objdump 。

环境

Linux, 请不要使用 Windows :)

过程

分析

执行 bomb 程序

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➜  bomb git:(master) ./bomb          
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!

一切正常。查看 bomb.c 程序:

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/***************************************************************************
* Dr. Evil's Insidious Bomb, Version 1.1
* Copyright 2011, Dr. Evil Incorporated. All rights reserved.
*
* LICENSE:
*
* Dr. Evil Incorporated (the PERPETRATOR) hereby grants you (the
* VICTIM) explicit permission to use this bomb (the BOMB). This is a
* time limited license, which expires on the death of the VICTIM.
* The PERPETRATOR takes no responsibility for damage, frustration,
* insanity, bug-eyes, carpal-tunnel syndrome, loss of sleep, or other
* harm to the VICTIM. Unless the PERPETRATOR wants to take credit,
* that is. The VICTIM may not distribute this bomb source code to
* any enemies of the PERPETRATOR. No VICTIM may debug,
* reverse-engineer, run "strings" on, decompile, decrypt, or use any
* other technique to gain knowledge of and defuse the BOMB. BOMB
* proof clothing may not be worn when handling this program. The
* PERPETRATOR will not apologize for the PERPETRATOR's poor sense of
* humor. This license is null and void where the BOMB is prohibited
* by law.
***************************************************************************/

#include <stdio.h>
#include <stdlib.h>
#include "support.h"
#include "phases.h"

/*
* Note to self: Remember to erase this file so my victims will have no
* idea what is going on, and so they will all blow up in a
* spectaculary fiendish explosion. -- Dr. Evil
*/

FILE *infile;

int main(int argc, char *argv[])
{
char *input;

/* Note to self: remember to port this bomb to Windows and put a
* fantastic GUI on it. */

/* When run with no arguments, the bomb reads its input lines
* from standard input. */
if (argc == 1) {
infile = stdin;
}

/* When run with one argument <file>, the bomb reads from <file>
* until EOF, and then switches to standard input. Thus, as you
* defuse each phase, you can add its defusing string to <file> and
* avoid having to retype it. */
else if (argc == 2) {
if (!(infile = fopen(argv[1], "r"))) {
printf("%s: Error: Couldn't open %s\n", argv[0], argv[1]);
exit(8);
}
}

/* You can't call the bomb with more than 1 command line argument. */
else {
printf("Usage: %s [<input_file>]\n", argv[0]);
exit(8);
}

/* Do all sorts of secret stuff that makes the bomb harder to defuse. */
initialize_bomb();

printf("Welcome to my fiendish little bomb. You have 6 phases with\n");
printf("which to blow yourself up. Have a nice day!\n");

/* Hmm... Six phases must be more secure than one phase! */
input = read_line(); /* Get input */
phase_1(input); /* Run the phase */
phase_defused(); /* Drat! They figured it out!
* Let me know how they did it. */
printf("Phase 1 defused. How about the next one?\n");

/* The second phase is harder. No one will ever figure out
* how to defuse this... */
input = read_line();
phase_2(input);
phase_defused();
printf("That's number 2. Keep going!\n");

/* I guess this is too easy so far. Some more complex code will
* confuse people. */
input = read_line();
phase_3(input);
phase_defused();
printf("Halfway there!\n");

/* Oh yeah? Well, how good is your math? Try on this saucy problem! */
input = read_line();
phase_4(input);
phase_defused();
printf("So you got that one. Try this one.\n");

/* Round and 'round in memory we go, where we stop, the bomb blows! */
input = read_line();
phase_5(input);
phase_defused();
printf("Good work! On to the next...\n");

/* This phase will never be used, since no one will get past the
* earlier ones. But just in case, make this one extra hard. */
input = read_line();
phase_6(input);
phase_defused();

/* Wow, they got it! But isn't something... missing? Perhaps
* something they overlooked? Mua ha ha ha ha! */

return 0;
}

由 45-64行可知, bomb程序可以通过标准输入和文件执行, 指定相应的文件在第二个参数。使用我已经破解的结果文件运行。

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➜  bomb git:(master) ./bomb ./result
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Phase 1 defused. How about the next one?
That's number 2. Keep going!
Halfway there!
So you got that one. Try this one.
Good work! On to the next...
Congratulations! You've defused the bomb!

没有任何问题。毫无疑问,首先反汇编。

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➜  bomb git:(master) ✗ objdump -d bomb > assemblycode

查看 main 处代码段。

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0000000000400da0 <main>:
400da0: 53 push %rbx
400da1: 83 ff 01 cmp $0x1,%edi
400da4: 75 10 jne 400db6 <main+0x16>
400da6: 48 8b 05 9b 29 20 00 mov 0x20299b(%rip),%rax # 603748 <stdin@@GLIBC_2.2.5>
400dad: 48 89 05 b4 29 20 00 mov %rax,0x2029b4(%rip) # 603768 <infile>
400db4: eb 63 jmp 400e19 <main+0x79>
400db6: 48 89 f3 mov %rsi,%rbx
400db9: 83 ff 02 cmp $0x2,%edi
400dbc: 75 3a jne 400df8 <main+0x58>
400dbe: 48 8b 7e 08 mov 0x8(%rsi),%rdi
400dc2: be b4 22 40 00 mov $0x4022b4,%esi
400dc7: e8 44 fe ff ff callq 400c10 <fopen@plt>
400dcc: 48 89 05 95 29 20 00 mov %rax,0x202995(%rip) # 603768 <infile>
400dd3: 48 85 c0 test %rax,%rax
400dd6: 75 41 jne 400e19 <main+0x79>
400dd8: 48 8b 4b 08 mov 0x8(%rbx),%rcx
400ddc: 48 8b 13 mov (%rbx),%rdx
400ddf: be b6 22 40 00 mov $0x4022b6,%esi
400de4: bf 01 00 00 00 mov $0x1,%edi
400de9: e8 12 fe ff ff callq 400c00 <__printf_chk@plt>
400dee: bf 08 00 00 00 mov $0x8,%edi
400df3: e8 28 fe ff ff callq 400c20 <exit@plt>
400df8: 48 8b 16 mov (%rsi),%rdx
400dfb: be d3 22 40 00 mov $0x4022d3,%esi
400e00: bf 01 00 00 00 mov $0x1,%edi
400e05: b8 00 00 00 00 mov $0x0,%eax
400e0a: e8 f1 fd ff ff callq 400c00 <__printf_chk@plt>
400e0f: bf 08 00 00 00 mov $0x8,%edi
400e14: e8 07 fe ff ff callq 400c20 <exit@plt>
400e19: e8 84 05 00 00 callq 4013a2 <initialize_bomb>
400e1e: bf 38 23 40 00 mov $0x402338,%edi
400e23: e8 e8 fc ff ff callq 400b10 <puts@plt>
400e28: bf 78 23 40 00 mov $0x402378,%edi
400e2d: e8 de fc ff ff callq 400b10 <puts@plt>
400e32: e8 67 06 00 00 callq 40149e <read_line>
400e37: 48 89 c7 mov %rax,%rdi
400e3a: e8 a1 00 00 00 callq 400ee0 <phase_1>
400e3f: e8 80 07 00 00 callq 4015c4 <phase_defused>
400e44: bf a8 23 40 00 mov $0x4023a8,%edi
400e49: e8 c2 fc ff ff callq 400b10 <puts@plt>
400e4e: e8 4b 06 00 00 callq 40149e <read_line>
400e53: 48 89 c7 mov %rax,%rdi
400e56: e8 a1 00 00 00 callq 400efc <phase_2>
400e5b: e8 64 07 00 00 callq 4015c4 <phase_defused>
400e60: bf ed 22 40 00 mov $0x4022ed,%edi
400e65: e8 a6 fc ff ff callq 400b10 <puts@plt>
400e6a: e8 2f 06 00 00 callq 40149e <read_line>
400e6f: 48 89 c7 mov %rax,%rdi
400e72: e8 cc 00 00 00 callq 400f43 <phase_3>
400e77: e8 48 07 00 00 callq 4015c4 <phase_defused>
400e7c: bf 0b 23 40 00 mov $0x40230b,%edi
400e81: e8 8a fc ff ff callq 400b10 <puts@plt>
400e86: e8 13 06 00 00 callq 40149e <read_line>
400e8b: 48 89 c7 mov %rax,%rdi
400e8e: e8 79 01 00 00 callq 40100c <phase_4>
400e93: e8 2c 07 00 00 callq 4015c4 <phase_defused>
400e98: bf d8 23 40 00 mov $0x4023d8,%edi
400e9d: e8 6e fc ff ff callq 400b10 <puts@plt>
400ea2: e8 f7 05 00 00 callq 40149e <read_line>
400ea7: 48 89 c7 mov %rax,%rdi
400eaa: e8 b3 01 00 00 callq 401062 <phase_5>
400eaf: e8 10 07 00 00 callq 4015c4 <phase_defused>
400eb4: bf 1a 23 40 00 mov $0x40231a,%edi
400eb9: e8 52 fc ff ff callq 400b10 <puts@plt>
400ebe: e8 db 05 00 00 callq 40149e <read_line>
400ec3: 48 89 c7 mov %rax,%rdi
400ec6: e8 29 02 00 00 callq 4010f4 <phase_6>
400ecb: e8 f4 06 00 00 callq 4015c4 <phase_defused>
400ed0: b8 00 00 00 00 mov $0x0,%eax
400ed5: 5b pop %rbx
400ed6: c3 retq
400ed7: 90 nop
400ed8: 90 nop
400ed9: 90 nop
400eda: 90 nop
400edb: 90 nop
400edc: 90 nop
400edd: 90 nop
400ede: 90 nop
400edf: 90 nop

第一个短语

查看 bomb.c 第73行可知: readline 函数返回指向输入的第一个字符的指针。

查看 main 函数第36-38行。

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400e32:    e8 67 06 00 00           callq  40149e <read_line>
400e37: 48 89 c7 mov %rax,%rdi
400e3a: e8 a1 00 00 00 callq 400ee0 <phase_1>
  • 1 调用 read_line 函数
  • 2 read_line 函数返回结果存在 rax 寄存器, 将其移入 rdi 寄存器,作为之后函数的第一个参数。
  • 3 调用 phase_1 函数。

输入的字符指针作为第一个参数,一切都是那么的自然。根据38行指定的地址,查看 phase_1 函数汇编代码。

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0000000000400ee0 <phase_1>:
400ee0: 48 83 ec 08 sub $0x8,%rsp
400ee4: be 00 24 40 00 mov $0x402400,%esi
400ee9: e8 4a 04 00 00 callq 401338 <strings_not_equal>
400eee: 85 c0 test %eax,%eax
400ef0: 74 05 je 400ef7 <phase_1+0x17>
400ef2: e8 43 05 00 00 callq 40143a <explode_bomb>
400ef7: 48 83 c4 08 add $0x8,%rsp
400efb: c3 retq

查看2-3行。

  • 2 内存地址 0x402400 移入 esi寄存器
  • 3 调用 strings_not_equal 函数,此时 rdi 为 input

从 strings_not_equal 函数名称和它所对应的两个参数可以知道:
input 应该和对应内存位置字符串相等。

我们使用 gdb 查看对应内存位置字符串:

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➜  bomb git:(master) gdb bomb
GNU gdb (Ubuntu 9.1-0ubuntu1) 9.1
Copyright (C) 2020 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
Type "show copying" and "show warranty" for details.
This GDB was configured as "x86_64-linux-gnu".
Type "show configuration" for configuration details.
For bug reporting instructions, please see:
<http://www.gnu.org/software/gdb/bugs/>.
Find the GDB manual and other documentation resources online at:
<http://www.gnu.org/software/gdb/documentation/>.

For help, type "help".
Type "apropos word" to search for commands related to "word"...
Reading symbols from bomb...
(gdb) p (char*)0x402400
$1 = 0x402400 "Border relations with Canada have never been better."
(gdb)

尝试运行 bomb 程序输入对应字符串试试:

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?

是的,我们成功了!

第四行之后的汇编代码主要是:如果函数返回0,成功返回。不是0,调用 explode_bomb 函数,代表着我们的输入失败了。

第二个短语

查看 main 函数第 42-44 行。

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400e4e:    e8 4b 06 00 00           callq  40149e <read_line>
400e53: 48 89 c7 mov %rax,%rdi
400e56: e8 a1 00 00 00 callq 400efc <phase_2>

和第一个方式相同,不再赘述。

查看对应位置 phase_2 汇编代码。

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0000000000400efc <phase_2>:
400efc: 55 push %rbp
400efd: 53 push %rbx
400efe: 48 83 ec 28 sub $0x28,%rsp
400f02: 48 89 e6 mov %rsp,%rsi
400f05: e8 52 05 00 00 callq 40145c <read_six_numbers>
400f0a: 83 3c 24 01 cmpl $0x1,(%rsp)
400f0e: 74 20 je 400f30 <phase_2+0x34>
400f10: e8 25 05 00 00 callq 40143a <explode_bomb>
400f15: eb 19 jmp 400f30 <phase_2+0x34>
400f17: 8b 43 fc mov -0x4(%rbx),%eax
400f1a: 01 c0 add %eax,%eax
400f1c: 39 03 cmp %eax,(%rbx)
400f1e: 74 05 je 400f25 <phase_2+0x29>
400f20: e8 15 05 00 00 callq 40143a <explode_bomb>
400f25: 48 83 c3 04 add $0x4,%rbx
400f29: 48 39 eb cmp %rbp,%rbx
400f2c: 75 e9 jne 400f17 <phase_2+0x1b>
400f2e: eb 0c jmp 400f3c <phase_2+0x40>
400f30: 48 8d 5c 24 04 lea 0x4(%rsp),%rbx
400f35: 48 8d 6c 24 18 lea 0x18(%rsp),%rbp
400f3a: eb db jmp 400f17 <phase_2+0x1b>
400f3c: 48 83 c4 28 add $0x28,%rsp
400f40: 5b pop %rbx
400f41: 5d pop %rbp
400f42: c3 retq
  • 3-6: 将6个数字读到栈上。
  • 7-9: 第一个数字不为1, 炸弹爆炸, 为1,跳到20行
  • 10-26:检查每个数字是否为上个数字的2倍,不是则炸弹爆炸。

所以答案应该是: 1 2 4 8 16 32

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!

第三个短语

查看 main 函数48-50行。

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400e6a:    e8 2f 06 00 00           callq  40149e <read_line>
400e6f: 48 89 c7 mov %rax,%rdi
400e72: e8 cc 00 00 00 callq 400f43 <phase_3>

查看对应位置的 phase_3 代码段:

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0000000000400f43 <phase_3>:
400f43: 48 83 ec 18 sub $0x18,%rsp
400f47: 48 8d 4c 24 0c lea 0xc(%rsp),%rcx
400f4c: 48 8d 54 24 08 lea 0x8(%rsp),%rdx
400f51: be cf 25 40 00 mov $0x4025cf,%esi
400f56: b8 00 00 00 00 mov $0x0,%eax
400f5b: e8 90 fc ff ff callq 400bf0 <__isoc99_sscanf@plt>
400f60: 83 f8 01 cmp $0x1,%eax
400f63: 7f 05 jg 400f6a <phase_3+0x27>
400f65: e8 d0 04 00 00 callq 40143a <explode_bomb>
400f6a: 83 7c 24 08 07 cmpl $0x7,0x8(%rsp)
400f6f: 77 3c ja 400fad <phase_3+0x6a>
400f71: 8b 44 24 08 mov 0x8(%rsp),%eax
400f75: ff 24 c5 70 24 40 00 jmpq *0x402470(,%rax,8)
400f7c: b8 cf 00 00 00 mov $0xcf,%eax
400f81: eb 3b jmp 400fbe <phase_3+0x7b>
400f83: b8 c3 02 00 00 mov $0x2c3,%eax
400f88: eb 34 jmp 400fbe <phase_3+0x7b>
400f8a: b8 00 01 00 00 mov $0x100,%eax
400f8f: eb 2d jmp 400fbe <phase_3+0x7b>
400f91: b8 85 01 00 00 mov $0x185,%eax
400f96: eb 26 jmp 400fbe <phase_3+0x7b>
400f98: b8 ce 00 00 00 mov $0xce,%eax
400f9d: eb 1f jmp 400fbe <phase_3+0x7b>
400f9f: b8 aa 02 00 00 mov $0x2aa,%eax
400fa4: eb 18 jmp 400fbe <phase_3+0x7b>
400fa6: b8 47 01 00 00 mov $0x147,%eax
400fab: eb 11 jmp 400fbe <phase_3+0x7b>
400fad: e8 88 04 00 00 callq 40143a <explode_bomb>
400fb2: b8 00 00 00 00 mov $0x0,%eax
400fb7: eb 05 jmp 400fbe <phase_3+0x7b>
400fb9: b8 37 01 00 00 mov $0x137,%eax
400fbe: 3b 44 24 0c cmp 0xc(%rsp),%eax
400fc2: 74 05 je 400fc9 <phase_3+0x86>
400fc4: e8 71 04 00 00 callq 40143a <explode_bomb>
400fc9: 48 83 c4 18 add $0x18,%rsp
400fcd: c3 retq

gdb 打印第5行内存内容

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➜  bomb git:(master) gdb bomb
GNU gdb (Ubuntu 9.1-0ubuntu1) 9.1
Copyright (C) 2020 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
Type "show copying" and "show warranty" for details.
This GDB was configured as "x86_64-linux-gnu".
Type "show configuration" for configuration details.
For bug reporting instructions, please see:
<http://www.gnu.org/software/gdb/bugs/>.
Find the GDB manual and other documentation resources online at:
<http://www.gnu.org/software/gdb/documentation/>.

For help, type "help".
Type "apropos word" to search for commands related to "word"...
Reading symbols from bomb...
(gdb) p (char*)0x4025cf
$1 = 0x4025cf "%d %d"
(gdb)
  • 7-10: 输入最少为两个整数
  • 11-37: 第一个数 <= 7, 第二个数由第一个数所计算出来的内存位置所决定

由第14行可知:跳转地址为 0x402470 + (第一个数 * 8) 地址所对应的值

gdb 查看 0x402470 附近100个字节的内容

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(gdb) x/100x 0x402470
0x402470: 0x00400f7c 0x00000000 0x00400fb9 0x00000000
0x402480: 0x00400f83 0x00000000 0x00400f8a 0x00000000
0x402490: 0x00400f91 0x00000000 0x00400f98 0x00000000
0x4024a0: 0x00400f9f 0x00000000 0x00400fa6 0x00000000
0x4024b0 <array.3449>: 0x7564616d 0x73726569 0x746f666e 0x6c796276
0x4024c0: 0x79206f53 0x7420756f 0x6b6e6968 0x756f7920
0x4024d0: 0x6e616320 0x6f747320 0x68742070 0x6f622065
0x4024e0: 0x7720626d 0x20687469 0x6c727463 0x202c632d
0x4024f0: 0x79206f64 0x003f756f 0x73727543 0x202c7365
0x402500: 0x27756f79 0x66206576 0x646e756f 0x65687420
0x402510: 0x63657320 0x20746572 0x73616870 0x00002165
0x402520: 0x20747542 0x646e6966 0x20676e69 0x61207469
0x402530: 0x7320646e 0x69766c6f 0x6920676e 0x72612074
0x402540: 0x75712065 0x20657469 0x66666964 0x6e657265
0x402550: 0x2e2e2e74 0x00000000 0x676e6f43 0x75746172
0x402560: 0x6974616c 0x21736e6f 0x756f5920 0x20657627
0x402570: 0x75666564 0x20646573 0x20656874 0x626d6f62
0x402580: 0x65570021 0x2e2e6c6c 0x4b4f002e 0x2d3a202e
0x402590: 0x6e490029 0x696c6176 0x68702064 0x25657361
0x4025a0: 0x0a000a73 0x4d4f4f42 0x00212121 0x20656854
0x4025b0: 0x626d6f62 0x73616820 0x6f6c6220 0x75206e77
0x4025c0: 0x25002e70 0x64252064 0x20642520 0x25206425
0x4025d0: 0x64252064 0x72724500 0x203a726f 0x6d657250
0x4025e0: 0x72757461 0x4f452065 0x6e6f2046 0x64747320
0x4025f0: 0x47006e69 0x45444152 0x4d4f425f 0x72450042
(gdb)

可以得到两个数字的 8 个组合。
(0, 207) (1, 311) (2, 707) (3, 256) (4, 389) (5, 206) (6, 682) (7, 327)

输入这八个数字,都正确:

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➜  bomb git:(master) ./bomb 
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
0 207
Halfway there!

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
1 311
Halfway there!

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
2 707
Halfway there!

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➜  bomb git:(master) ./bomb         
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
3 256
Halfway there!

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
4 389
Halfway there!

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
5 206
Halfway there!

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
6 682
Halfway there!

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
7 327
Halfway there!

正如之前所分析的,在这两个数字之后加入任意内容都不影响我们第三个短语的成功

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
7 327 ardxwe 158
Halfway there!

一切都是那么的自然

第四个短语

查看 main 函数 54-56 行:

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400e86:    e8 13 06 00 00           callq  40149e <read_line>
400e8b: 48 89 c7 mov %rax,%rdi
400e8e: e8 79 01 00 00 callq 40100c <phase_4>

输入字符的指针传递给 phase_4 作为第一个参数,查看 phase_4 对应位置汇编代码。由于这里 phase_4 调用了 func4 函数,因此将 func4 一并贴出。

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0000000000400fce <func4>:
400fce: 48 83 ec 08 sub $0x8,%rsp
400fd2: 89 d0 mov %edx,%eax
400fd4: 29 f0 sub %esi,%eax
400fd6: 89 c1 mov %eax,%ecx
400fd8: c1 e9 1f shr $0x1f,%ecx
400fdb: 01 c8 add %ecx,%eax
400fdd: d1 f8 sar %eax
400fdf: 8d 0c 30 lea (%rax,%rsi,1),%ecx
400fe2: 39 f9 cmp %edi,%ecx
400fe4: 7e 0c jle 400ff2 <func4+0x24>
400fe6: 8d 51 ff lea -0x1(%rcx),%edx
400fe9: e8 e0 ff ff ff callq 400fce <func4>
400fee: 01 c0 add %eax,%eax
400ff0: eb 15 jmp 401007 <func4+0x39>
400ff2: b8 00 00 00 00 mov $0x0,%eax
400ff7: 39 f9 cmp %edi,%ecx
400ff9: 7d 0c jge 401007 <func4+0x39>
400ffb: 8d 71 01 lea 0x1(%rcx),%esi
400ffe: e8 cb ff ff ff callq 400fce <func4>
401003: 8d 44 00 01 lea 0x1(%rax,%rax,1),%eax
401007: 48 83 c4 08 add $0x8,%rsp
40100b: c3 retq

000000000040100c <phase_4>:
40100c: 48 83 ec 18 sub $0x18,%rsp
401010: 48 8d 4c 24 0c lea 0xc(%rsp),%rcx
401015: 48 8d 54 24 08 lea 0x8(%rsp),%rdx
40101a: be cf 25 40 00 mov $0x4025cf,%esi
40101f: b8 00 00 00 00 mov $0x0,%eax
401024: e8 c7 fb ff ff callq 400bf0 <__isoc99_sscanf@plt>
401029: 83 f8 02 cmp $0x2,%eax
40102c: 75 07 jne 401035 <phase_4+0x29>
40102e: 83 7c 24 08 0e cmpl $0xe,0x8(%rsp)
401033: 76 05 jbe 40103a <phase_4+0x2e>
401035: e8 00 04 00 00 callq 40143a <explode_bomb>
40103a: ba 0e 00 00 00 mov $0xe,%edx
40103f: be 00 00 00 00 mov $0x0,%esi
401044: 8b 7c 24 08 mov 0x8(%rsp),%edi
401048: e8 81 ff ff ff callq 400fce <func4>
40104d: 85 c0 test %eax,%eax
40104f: 75 07 jne 401058 <phase_4+0x4c>
401051: 83 7c 24 0c 00 cmpl $0x0,0xc(%rsp)
401056: 74 05 je 40105d <phase_4+0x51>
401058: e8 dd 03 00 00 callq 40143a <explode_bomb>
40105d: 48 83 c4 18 add $0x18,%rsp
401061: c3 retq
  • 29-33: 需要两个参数, 至于参数具体格式, 可以通过查看 esi 寄存器存储的内存地址内容
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(gdb) p (char*)0x4025cf
$2 = 0x4025cf "%d %d"

显然,刚好需要两个整数。

  • 34-47:第一个参数 <= 15,调用 func4的返回值应该是0,第二个数字是0

仔细分析 func4, 15 >> 1 == 7,如果输入是7,刚好满足 jle 和 jge 的条件, 而且 rax = 0, 满足题意,故答案为(7, 0)

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
0 207
Halfway there!
7 0
So you got that one. Try this one.

第五个短语

查看 main 函数第 60-62 行:

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400ea2:    e8 f7 05 00 00           callq  40149e <read_line>
400ea7: 48 89 c7 mov %rax,%rdi
400eaa: e8 b3 01 00 00 callq 401062 <phase_5>

查看 phase_5 对应汇编代码:

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0000000000401062 <phase_5>:
401062: 53 push %rbx
401063: 48 83 ec 20 sub $0x20,%rsp
401067: 48 89 fb mov %rdi,%rbx
40106a: 64 48 8b 04 25 28 00 mov %fs:0x28,%rax
401071: 00 00
401073: 48 89 44 24 18 mov %rax,0x18(%rsp)
401078: 31 c0 xor %eax,%eax
40107a: e8 9c 02 00 00 callq 40131b <string_length>
40107f: 83 f8 06 cmp $0x6,%eax
401082: 74 4e je 4010d2 <phase_5+0x70>
401084: e8 b1 03 00 00 callq 40143a <explode_bomb>
401089: eb 47 jmp 4010d2 <phase_5+0x70>
40108b: 0f b6 0c 03 movzbl (%rbx,%rax,1),%ecx
40108f: 88 0c 24 mov %cl,(%rsp)
401092: 48 8b 14 24 mov (%rsp),%rdx
401096: 83 e2 0f and $0xf,%edx
401099: 0f b6 92 b0 24 40 00 movzbl 0x4024b0(%rdx),%edx
4010a0: 88 54 04 10 mov %dl,0x10(%rsp,%rax,1)
4010a4: 48 83 c0 01 add $0x1,%rax
4010a8: 48 83 f8 06 cmp $0x6,%rax
4010ac: 75 dd jne 40108b <phase_5+0x29>
4010ae: c6 44 24 16 00 movb $0x0,0x16(%rsp)
4010b3: be 5e 24 40 00 mov $0x40245e,%esi
4010b8: 48 8d 7c 24 10 lea 0x10(%rsp),%rdi
4010bd: e8 76 02 00 00 callq 401338 <strings_not_equal>
4010c2: 85 c0 test %eax,%eax
4010c4: 74 13 je 4010d9 <phase_5+0x77>
4010c6: e8 6f 03 00 00 callq 40143a <explode_bomb>
4010cb: 0f 1f 44 00 00 nopl 0x0(%rax,%rax,1)
4010d0: eb 07 jmp 4010d9 <phase_5+0x77>
4010d2: b8 00 00 00 00 mov $0x0,%eax
4010d7: eb b2 jmp 40108b <phase_5+0x29>
4010d9: 48 8b 44 24 18 mov 0x18(%rsp),%rax
4010de: 64 48 33 04 25 28 00 xor %fs:0x28,%rax
4010e5: 00 00
4010e7: 74 05 je 4010ee <phase_5+0x8c>
4010e9: e8 42 fa ff ff callq 400b30 <__stack_chk_fail@plt>
4010ee: 48 83 c4 20 add $0x20,%rsp
4010f2: 5b pop %rbx
4010f3: c3 retq
  • 9-10: 字符串长度为6
  • 13-41: 每个字符对应字节后四位作为偏移,以 0x4024b0 作为基地址,最终和 0x40245e 内存地址做比较。
    使用 gdb 查看相应内存地址内容:
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(gdb) p (char*)0x40245e
$1 = 0x40245e "flyers"
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(gdb) p (char*)0x4024b0
$2 = 0x4024b0 <array> "maduiersnfotvbylSo you think you can stop the bomb with ctrl-c, do you?"

为了得到 flyers, 需要的偏移地址为 9fe567,理论上 ASCII 码可打印字符均可。

故答案为 9?>567 或者 y_^UVW 等等 只要满足最后四位要求即可。

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
7 327
Halfway there!
7 0
So you got that one. Try this one.
9?>567
Good work! On to the next...
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➜  bomb git:(master) ./bomb         
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
7 327
Halfway there!
7 0
So you got that one. Try this one.
y_^UVW
Good work! On to the next...

我们成功了!

第六个短语

查看 main 函数第 66-68 行

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400ebe:    e8 db 05 00 00           callq  40149e <read_line>
400ec3: 48 89 c7 mov %rax,%rdi
400ec6: e8 29 02 00 00 callq 4010f4 <phase_6>

查看内存地址 0x4010f4

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00000000004010f4 <phase_6>:
4010f4: 41 56 push %r14
4010f6: 41 55 push %r13
4010f8: 41 54 push %r12
4010fa: 55 push %rbp
4010fb: 53 push %rbx
4010fc: 48 83 ec 50 sub $0x50,%rsp
401100: 49 89 e5 mov %rsp,%r13
401103: 48 89 e6 mov %rsp,%rsi
401106: e8 51 03 00 00 callq 40145c <read_six_numbers>
40110b: 49 89 e6 mov %rsp,%r14
40110e: 41 bc 00 00 00 00 mov $0x0,%r12d
401114: 4c 89 ed mov %r13,%rbp
401117: 41 8b 45 00 mov 0x0(%r13),%eax
40111b: 83 e8 01 sub $0x1,%eax
40111e: 83 f8 05 cmp $0x5,%eax
401121: 76 05 jbe 401128 <phase_6+0x34>
401123: e8 12 03 00 00 callq 40143a <explode_bomb>
401128: 41 83 c4 01 add $0x1,%r12d
40112c: 41 83 fc 06 cmp $0x6,%r12d
401130: 74 21 je 401153 <phase_6+0x5f>
401132: 44 89 e3 mov %r12d,%ebx
401135: 48 63 c3 movslq %ebx,%rax
401138: 8b 04 84 mov (%rsp,%rax,4),%eax
40113b: 39 45 00 cmp %eax,0x0(%rbp)
40113e: 75 05 jne 401145 <phase_6+0x51>
401140: e8 f5 02 00 00 callq 40143a <explode_bomb>
401145: 83 c3 01 add $0x1,%ebx
401148: 83 fb 05 cmp $0x5,%ebx
40114b: 7e e8 jle 401135 <phase_6+0x41>
40114d: 49 83 c5 04 add $0x4,%r13
401151: eb c1 jmp 401114 <phase_6+0x20>
401153: 48 8d 74 24 18 lea 0x18(%rsp),%rsi
401158: 4c 89 f0 mov %r14,%rax
40115b: b9 07 00 00 00 mov $0x7,%ecx
401160: 89 ca mov %ecx,%edx
401162: 2b 10 sub (%rax),%edx
401164: 89 10 mov %edx,(%rax)
401166: 48 83 c0 04 add $0x4,%rax
40116a: 48 39 f0 cmp %rsi,%rax
40116d: 75 f1 jne 401160 <phase_6+0x6c>
40116f: be 00 00 00 00 mov $0x0,%esi
401174: eb 21 jmp 401197 <phase_6+0xa3>
401176: 48 8b 52 08 mov 0x8(%rdx),%rdx
40117a: 83 c0 01 add $0x1,%eax
40117d: 39 c8 cmp %ecx,%eax
40117f: 75 f5 jne 401176 <phase_6+0x82>
401181: eb 05 jmp 401188 <phase_6+0x94>
401183: ba d0 32 60 00 mov $0x6032d0,%edx
401188: 48 89 54 74 20 mov %rdx,0x20(%rsp,%rsi,2)
40118d: 48 83 c6 04 add $0x4,%rsi
401191: 48 83 fe 18 cmp $0x18,%rsi
401195: 74 14 je 4011ab <phase_6+0xb7>
401197: 8b 0c 34 mov (%rsp,%rsi,1),%ecx
40119a: 83 f9 01 cmp $0x1,%ecx
40119d: 7e e4 jle 401183 <phase_6+0x8f>
40119f: b8 01 00 00 00 mov $0x1,%eax
4011a4: ba d0 32 60 00 mov $0x6032d0,%edx
4011a9: eb cb jmp 401176 <phase_6+0x82>
4011ab: 48 8b 5c 24 20 mov 0x20(%rsp),%rbx
4011b0: 48 8d 44 24 28 lea 0x28(%rsp),%rax
4011b5: 48 8d 74 24 50 lea 0x50(%rsp),%rsi
4011ba: 48 89 d9 mov %rbx,%rcx
4011bd: 48 8b 10 mov (%rax),%rdx
4011c0: 48 89 51 08 mov %rdx,0x8(%rcx)
4011c4: 48 83 c0 08 add $0x8,%rax
4011c8: 48 39 f0 cmp %rsi,%rax
4011cb: 74 05 je 4011d2 <phase_6+0xde>
4011cd: 48 89 d1 mov %rdx,%rcx
4011d0: eb eb jmp 4011bd <phase_6+0xc9>
4011d2: 48 c7 42 08 00 00 00 movq $0x0,0x8(%rdx)
4011d9: 00
4011da: bd 05 00 00 00 mov $0x5,%ebp
4011df: 48 8b 43 08 mov 0x8(%rbx),%rax
4011e3: 8b 00 mov (%rax),%eax
4011e5: 39 03 cmp %eax,(%rbx)
4011e7: 7d 05 jge 4011ee <phase_6+0xfa>
4011e9: e8 4c 02 00 00 callq 40143a <explode_bomb>
4011ee: 48 8b 5b 08 mov 0x8(%rbx),%rbx
4011f2: 83 ed 01 sub $0x1,%ebp
4011f5: 75 e8 jne 4011df <phase_6+0xeb>
4011f7: 48 83 c4 50 add $0x50,%rsp
4011fb: 5b pop %rbx
4011fc: 5d pop %rbp
4011fd: 41 5c pop %r12
4011ff: 41 5d pop %r13
401201: 41 5e pop %r14
401203: c3 retq

或许看到如此冗长的汇编代码你会感到茫然,其实没有什么难度,多点耐心就好。

主要表达的是:

  • 共有六个数字,每个数字 <= 6
  • 每个数字执行固定操作 取反 + 7
  • 用操作后的数字作为取址次数,0x6032d0作为基地址,按顺序将对应内存位置 + 8 的内容存储到堆栈。
  • 按顺序,堆栈处所存储地址对应的数字应该是递减的

查看 0x6032d0 内存内容:

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(gdb) x/100x 0x6032d0
0x6032d0 <node1>: 0x0000014c 0x00000001 0x006032e0 0x00000000
0x6032e0 <node2>: 0x000000a8 0x00000002 0x006032f0 0x00000000
0x6032f0 <node3>: 0x0000039c 0x00000003 0x00603300 0x00000000
0x603300 <node4>: 0x000002b3 0x00000004 0x00603310 0x00000000
0x603310 <node5>: 0x000001dd 0x00000005 0x00603320 0x00000000
0x603320 <node6>: 0x000001bb 0x00000006 0x00000000 0x00000000

对应内存地址内容从小到大排列应该是 0x6032f0 0x603300 0x603310 0x603320 0x6032d0 0x6032e0
循环次数应该是 2 3 4 5 0 1,注意到 main 函数第57行:

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40119f:    b8 01 00 00 00           mov    $0x1,%eax

比较时 eax 初始值为1,每操作一次,然后比较。所以,实际的值应该为 3 4 5 6 1 2,又因为一开始对数字进行取反加7的操作,所以本来的6个数字应该是 4 3 2 1 6 5

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➜  bomb git:(master) ./bomb
Welcome to my fiendish little bomb. You have 6 phases with
which to blow yourself up. Have a nice day!
Border relations with Canada have never been better.
Phase 1 defused. How about the next one?
1 2 4 8 16 32
That's number 2. Keep going!
7 327
Halfway there!
7 0
So you got that one. Try this one.
9?>567
Good work! On to the next...
4 3 2 1 6 5
Congratulations! You've defused the bomb!

全文完

任何建议或者疑问你可以发我邮件: ardxwe@gmail.com